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iBoaterer[_3_]

In article ,
says...

On Wednesday, June 12, 2013 8:36:01 AM UTC-4, iBoaterer wrote:

Okay, time for a simple physcis lesson...

Therefore the car has to have enough surface area, and
friction ability to to overcome 4 times the force.

The car has far more than 4 times the contact patch. And, the car also shifts its CG to load up the outside tires in a turn, applying more down force to them. And, the car applies it's down force (traction) in a turn like this:

_|_

while the bike is like this:

_\_

If the desired result is to not slide across the pavement, which do you think is more efficient way to apply down force to resist that tendency? You're concentrating on one tiny little aspect of the issue. Time to open your mind and that basic physics book!

Fact is, unless the track is specifically designed for the inherent weaknesses of bikes, cars almost always turn faster lap times. The ability to take the turns faster and better brakes more than makes up for the bike's better acceleration on most tracks.

ME "open that basic physics book"??? Please, do tell me the physics
behind your allegations. Now, for your first question, like I stated
earlier, the "more efficient way" to apply down force is to have the CG
more in line with the vector, which is what a motorcycles does when it
corners! Thanks for making my point!