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#1
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Sun's Location
By my fist sighting, I put the Sun 234 miles south of the Equator today.
Our winter is about to descend on Ozzy's land. Getting ready for; Welcome Sweet Springtime. in the Northern hemisphere. Soon to have Long Days and short nights at Lat. 48N. Returning at 2200 and docking in daylight. Ole Thom http://community.webtv.net/tassail/ThomsPage |
#2
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Thats great news Thom!
Joe |
#3
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Thom Stewart wrote:
By my fist sighting, I put the Sun 234 miles south of the Equator today. And by my planetarium sighting, it's declination today is just about 5degS. That would put it overhead at 300 miles south of the Equator. 234 miles equates to a declination of about -3.9 degrees. -- Wally www.artbywally.com/FiatPandaRally/index.htm www.wally.myby.co.uk |
#4
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Wally,
Admittedly my method is very crude but with 5 degrees to go to the Equinox that is about 3.3 days per degree and at this section of the seasonal sine wave that does sound rather fast for the revoltional speed of the earth. 3.9 was what I figured. That would be about .26 degrees a day. We'll know in about 15 days won't we? 4 equal seasons divided into a 365 day year would 91 1/4 days. At 3.3 days per degree the seasons would almost be 72 1/2 days long. I could be wrong and I know the rate varies ( Sine Wave) but I'm pretty sure the rate of change is the fastest crossing the Equator. My method is a guessation and I use the RMS rate for my guess. We'll see. 1.1 degree ( 60 miles +) in 75 days using no instruments and no tables, I'm pretty happy with the results Keep in touch Ole Thom http://community.webtv.net/tassail/ThomsPage |
#5
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Sun???Where????
"Thom Stewart" wrote in message ... Wally, Admittedly my method is very crude but with 5 degrees to go to the Equinox that is about 3.3 days per degree and at this section of the seasonal sine wave that does sound rather fast for the revoltional speed of the earth. 3.9 was what I figured. That would be about .26 degrees a day. We'll know in about 15 days won't we? 4 equal seasons divided into a 365 day year would 91 1/4 days. At 3.3 days per degree the seasons would almost be 72 1/2 days long. I could be wrong and I know the rate varies ( Sine Wave) but I'm pretty sure the rate of change is the fastest crossing the Equator. My method is a guessation and I use the RMS rate for my guess. We'll see. 1.1 degree ( 60 miles +) in 75 days using no instruments and no tables, I'm pretty happy with the results Keep in touch Ole Thom http://community.webtv.net/tassail/ThomsPage |
#6
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Good calculation Thom. It's not the revolutional speed of the earth it's the
precessional speed. It is the fastest at the equator and the dwell time is longest at the summer and winter equinoxes. The rate of change of a sine wave is a cosine wave. The cosine function is at a maximum of 1 when the argument is at 0 degrees. The argument used in the sine function for position should be the number of days away from the day with equal dark/light normalized to k*pi radians. The k is to fudge for complete darkness near the poles. It is extremely gratifying to see what is possible under the tutelage and inspiration of our own learned Master Mariner, the good Capt Neal. Ole Thom has clearly demonstrated that, good thinking Ole Thom! Amen! Bob Crantz "Thom Stewart" wrote in message ... Wally, Admittedly my method is very crude but with 5 degrees to go to the Equinox that is about 3.3 days per degree and at this section of the seasonal sine wave that does sound rather fast for the revoltional speed of the earth. 3.9 was what I figured. That would be about .26 degrees a day. We'll know in about 15 days won't we? 4 equal seasons divided into a 365 day year would 91 1/4 days. At 3.3 days per degree the seasons would almost be 72 1/2 days long. I could be wrong and I know the rate varies ( Sine Wave) but I'm pretty sure the rate of change is the fastest crossing the Equator. My method is a guessation and I use the RMS rate for my guess. We'll see. 1.1 degree ( 60 miles +) in 75 days using no instruments and no tables, I'm pretty happy with the results Keep in touch Ole Thom http://community.webtv.net/tassail/ThomsPage |
#7
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"Thom Stewart" wrote in message ... By my fist sighting, I put the Sun 234 miles south of the Equator today. Our winter is about to descend on Ozzy's land. Getting ready for; Welcome Sweet Springtime. in the Northern hemisphere. Soon to have Long Days and short nights at Lat. 48N. Returning at 2200 and docking in daylight. It's about F'ing time! Scotty |
#8
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Ah Scotty,
We must have winter or we would never truly know the joys of summer; we need nights to know the gift of daylight! Be still sad heart and stop repining; Behind the cloud is the still shining. Thy fate is the common fate of all; Into each life, some rain must fall. Some days must be dark a dreary!!! Good nite one and all. Time for Ole Thom to go to bed. |
#9
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This has been a weird Winter. On Monday it was 66*, nice warm breeze,
felt like a sailing day. Most of the snow melted. On Tuesday it dropped to 16*, snowing with 40mph winds. Ahhhhhhhhhhhhhhhhhh! Scotty "Thom Stewart" wrote in message ... Ah Scotty, We must have winter or we would never truly know the joys of summer; we need nights to know the gift of daylight! Be still sad heart and stop repining; Behind the cloud is the still shining. Thy fate is the common fate of all; Into each life, some rain must fall. Some days must be dark a dreary!!! Good nite one and all. Time for Ole Thom to go to bed. |
#10
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Wally,
I've got the Sun 180 miles south of the equator. What is the exact location? Ole Thom |
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