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#1
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I got my bilge pump controller put together and it looks pretty neat.
It will fit right under the fuse panel I put in and the relay can be easily pulled and replace. I tested it and my portable 12 V battery immediately gave the "Tink" that means the fuse blew. I checked and there were zero ohms across the terminals to the relay coil. I put this together very carefully so it was hard to believe I had a short. When I opened it up to look, I noticed that the suppression diode across the coil had burned into the wire slightly. I cut it and the short disappeared. I then cut the suppression diodes out of both relay sockets. There was no + or - indication on the relay wiring but one of the coil wires was red. Did I blow the diode by hooking up with reverse polarity? -- Roger Long |
#2
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Roger Long wrote:
I got my bilge pump controller put together and it looks pretty neat. It will fit right under the fuse panel I put in and the relay can be easily pulled and replace. I tested it and my portable 12 V battery immediately gave the "Tink" that means the fuse blew. I checked and there were zero ohms across the terminals to the relay coil. I put this together very carefully so it was hard to believe I had a short. When I opened it up to look, I noticed that the suppression diode across the coil had burned into the wire slightly. I cut it and the short disappeared. I then cut the suppression diodes out of both relay sockets. OOPS There was no + or - indication on the relay wiring but one of the coil wires was red. Did I blow the diode by hooking up with reverse polarity? YES, wrong polarity would put a massive current through the diode. Overcurrent is the quickest way to destroy a diode I know. Thhe usual failure mode for a diode is dead short unless you put enough current through it to physically rupture the package, when the short may change to an open circuit. As you have found, this results in total pump failure because the supply fuse has blown. :-( Removing the diodes is the correct thing to do. As you have now removed the protection they offered the switches and contacts, fit a snubber circuit across each relay coil. Snubbers are not polarity sensitive. It will work without them but for how long? They are not exactly expensive or difficult to fit. Can you clarify that the diodes were ONLY in the sockets, not inside the relays? At the moment I am concerned that if you plug in a replacement relay *with* a diode if the system is giving trouble, you may instantly blow the fuse rendering the pump totally dead. Relays with diodes usually have some polarity marking on the coil terminals. May just be a red dot, a tiny plus sign or even a circuit diagram showing the coil and the diode with pin numbers. Occasionally you get one that you have to read the manufacturer's databook to confirm it has a diode. -- Ian Malcolm. London, ENGLAND. (NEWSGROUP REPLY PREFERRED) ianm[at]the[dash]malcolms[dot]freeserve[dot]co[dot]uk [at]=@, [dash]=- & [dot]=. *Warning* HTML & 32K emails -- NUL: 'Stingo' Albacore #1554 - 15' Early 60's, Uffa Fox designed, All varnished hot moulded wooden racing dinghy. |
#3
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Yes the diodes were in the sockets. It makes sense then that the
relay had no polarity markings because it itself is not polarity sensitive. The red wire on the socket should have tipped me off but that's the problem with staying up late at night working on this stuff ![]() Here's a picture of the finished controller: http://home.maine.rr.com/rlma/Bilge.htm#Controller The diodes are way too sensitive a component to have buried inside a critical system box like this. I have the snubber components and will build them this morning. There is now nothing inside the box but wiring. Even if both relays should go bad, I can jumper a wire across the terminals to get the system pumping. I'll mark the box with the appropriate jumper location just in case. Thanks, (I should have included you in my header.) -- Roger Long "Ian Malcolm" wrote in message ... Roger Long wrote: I got my bilge pump controller put together and it looks pretty neat. It will fit right under the fuse panel I put in and the relay can be easily pulled and replace. I tested it and my portable 12 V battery immediately gave the "Tink" that means the fuse blew. I checked and there were zero ohms across the terminals to the relay coil. I put this together very carefully so it was hard to believe I had a short. When I opened it up to look, I noticed that the suppression diode across the coil had burned into the wire slightly. I cut it and the short disappeared. I then cut the suppression diodes out of both relay sockets. OOPS There was no + or - indication on the relay wiring but one of the coil wires was red. Did I blow the diode by hooking up with reverse polarity? YES, wrong polarity would put a massive current through the diode. Overcurrent is the quickest way to destroy a diode I know. Thhe usual failure mode for a diode is dead short unless you put enough current through it to physically rupture the package, when the short may change to an open circuit. As you have found, this results in total pump failure because the supply fuse has blown. :-( Removing the diodes is the correct thing to do. As you have now removed the protection they offered the switches and contacts, fit a snubber circuit across each relay coil. Snubbers are not polarity sensitive. It will work without them but for how long? They are not exactly expensive or difficult to fit. Can you clarify that the diodes were ONLY in the sockets, not inside the relays? At the moment I am concerned that if you plug in a replacement relay *with* a diode if the system is giving trouble, you may instantly blow the fuse rendering the pump totally dead. Relays with diodes usually have some polarity marking on the coil terminals. May just be a red dot, a tiny plus sign or even a circuit diagram showing the coil and the diode with pin numbers. Occasionally you get one that you have to read the manufacturer's databook to confirm it has a diode. -- Ian Malcolm. London, ENGLAND. (NEWSGROUP REPLY PREFERRED) ianm[at]the[dash]malcolms[dot]freeserve[dot]co[dot]uk [at]=@, [dash]=- & [dot]=. *Warning* HTML & 32K emails -- NUL: 'Stingo' Albacore #1554 - 15' Early 60's, Uffa Fox designed, All varnished hot moulded wooden racing dinghy. |
#4
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"Roger Long" wrote in
: Did I blow the diode by hooking up with reverse polarity? Yep. The diode only conducts when the field in the coil of the relay collapses, when you turn the power to it off. The diode is reverse biased (+ power to its banded cathode end, - power to its anode) when the relay is energized. You had it connected up backward, zapping the diode to a short. Oops.... +12-------coil----------12 | | --|-- band noband |
#5
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![]() "Larry W4CSC" wrote in message ... "Roger Long" wrote in : Did I blow the diode by hooking up with reverse polarity? Yep. The diode only conducts when the field in the coil of the relay collapses, when you turn the power to it off. The diode is reverse biased (+ power to its banded cathode end, - power to its anode) when the relay is energized. You had it connected up backward, zapping the diode to a short. Oops.... +12-------coil----------12 | | --|-- band noband Not clear. Fuse is blown but one would have to check to see if the diode is blown. Suppression diodes are generally rugged little things. They may well last long enough to blow the fuse without going out. There are only a zillion or two diodes launched in this application. I don't think I would use a solenoid or a relay without one. If worried get a bigger diode. |
#6
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Larry W4CSC wrote:
"Roger Long" wrote in : Did I blow the diode by hooking up with reverse polarity? Yep. The diode only conducts when the field in the coil of the relay collapses, when you turn the power to it off. The diode is reverse biased (+ power to its banded cathode end, - power to its anode) when the relay is energized. You had it connected up backward, zapping the diode to a short. Oops.... +12-------coil----------12 | | --|-- band noband I'm confused. Perhaps this is why I left hardware engineering for software. I thought the purpose of a diode was to pass current one way, and block it the other. Did this fail because the passed current was too high, or because the blocked voltage was too high? Or is there something else I'm missing? Should a small resistor have been put in series? Is the coil storing up too much energy? Why can't everything just be digital? While I'm on the subject, since I have twin engines, some of my instruments, such as the fuel gauge are fed by the key switch from one engine. Is there a way to hook up 2 diodes to allow either feed to work/ Radio Shack part numbers please ;-) |
#7
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Nope. It was a dead short. I'm putting in the 10 ohm / .01 mfd
suppressors instead. -- Roger Long |
#8
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Comments below:
"Jeff" wrote in message ... Larry W4CSC wrote: "Roger Long" wrote in : Did I blow the diode by hooking up with reverse polarity? Yep. The diode only conducts when the field in the coil of the relay collapses, when you turn the power to it off. The diode is reverse biased (+ power to its banded cathode end, - power to its anode) when the relay is energized. You had it connected up backward, zapping the diode to a short. Oops.... +12-------coil----------12 | | --|-- band noband I'm confused. Perhaps this is why I left hardware engineering for software. I thought the purpose of a diode was to pass current one way, and block it the other. Did this fail because the passed current was too high, or because the blocked voltage was too high? Or is there something else I'm missing? Simple answer, explained elsewhere, repeated here. Roger hooked his new sump pump system to a test battery to test it, but unfortunately connected the battery backwards (+ where - should have been). The diodes (two pumps, two relays, two diodes) normally would have blocked the 12 v. from the battery and passed only the reverse current from the collapsing relay coil field when the circuit opened. Instead, because the polarity of the circuit was reversed, the diode passed the full current available from the battery, essentially, the diode was a dead short accross the battery, so the diode(s) burned up and shorted itself (themselves) permanently. Rodger won't do that again I'll bet. Should a small resistor have been put in series? Is the coil storing up too much energy? Why can't everything just be digital? While I'm on the subject, since I have twin engines, some of my instruments, such as the fuel gauge are fed by the key switch from one engine. Is there a way to hook up 2 diodes to allow either feed to work/ Radio Shack part numbers please ;-) Yes, two diodes, arranged in a Y, each diode feeding power from each key switch coming together, then feeding power to the instruments you want to continue to operate with only one engine on. The diodes need to be rated at a high enough wattage (volts x amps = watts) to pass enough current to operate the instruments. There will be a slight voltage drop across the diodes so you may experience lower than expected readings on the instruments. -- Ken Heaton & Anne Tobin Cape Breton Island, Canada kenheaton AT ess wye dee DOT eastlink DOT ca |
#9
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Jeff wrote in :
I'm confused. Perhaps this is why I left hardware engineering for software. I thought the purpose of a diode was to pass current one way, and block it the other. Did this fail because the passed current was too high, or because the blocked voltage was too high? When he hooked it up backwards, the diode was forward biased straight across the battery's terminals. Current went through the roof, welding the junction to a short which, microseconds later, blew the fuse. Once welded to a short, unless you can really melt the mounting, it stays a short....across the coil, not in series with it. It's a short both ways at that point. This diode's function is to short the relay's coil when the coil's field collapses, producing inductive kick which forward biases the diode for a few milliseconds each time power is removed from the coil. Otherwise, the inductive kick, which could be several hundred volts for a few microseconds like the spark from an ignition coil, could destroy the control electronics or switch contacts which arc each time it is de-energized. With the diode in place, inductive kick produces .6v pulses, the forward bias voltage of the diode as it sinks the kick's power current pulse. Or is there something else I'm missing? Should a small resistor have been put in series? No, as the diode is normally REVERSE biased by the applied power. I doesn't conduct except for that little kick of the coil at de-energization. Is the coil storing up too much energy? Why can't everything just be digital? It is digital...(c; 1 = relay on.....0 = relay off...but it's not hexidecimal..making it harder for a software man to comprehend...hee hee. While I'm on the subject, since I have twin engines, some of my instruments, such as the fuel gauge are fed by the key switch from one engine. Is there a way to hook up 2 diodes to allow either feed to work/ Radio Shack part numbers please ;-) Any 1 amp, 50V piv or higher rectifier will work.....for this OR circuit...(c; Hook the anodes of the diodes, one to each power switch on each engine. Hook the cathodes (banded end) together to the common power + lead to each fuel guage. If either engine is turned on, its diode will conduct turning on both fuel guages. (classic OR gate - DDL logic!) engine 1----------------||---------\ \ \ engine 2----------------||------------\-----------fuel guage + Circuit may be too simple for mainframe engineers...(c; |
#10
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Roger Long wrote:
Yes the diodes were in the sockets. It makes sense then that the relay had no polarity markings because it itself is not polarity sensitive. The red wire on the socket should have tipped me off but that's the problem with staying up late at night working on this stuff ![]() Well I reckon you'll learn to get some sleep before working on expensive/critical stuff (if possible). :-) Here's a picture of the finished controller: http://home.maine.rr.com/rlma/Bilge.htm#Controller Nice to see the end result. The diodes are way too sensitive a component to have buried inside a critical system box like this. Its not that they are very sensitive, its their rather unpleasant failure mode. :-( This was why I and others were encouraging you to use snubbers instead. One can design them in safely but that can get way too technical for all except denisons of sci.electronics.design or similar 'wire headed' hangouts. :-) I have the snubber components and will build them this morning. There is now nothing inside the box but wiring. Even if both relays should go bad, I can jumper a wire across the terminals to get the system pumping. I'll mark the box with the appropriate jumper location just in case. Couple of spare relay going in your spares kit I hope. Might as well make up the jumper wire with appropriate ends and keep it taped to the box. Thanks, (I should have included you in my header.) No worries. B.T.W., I am off sailing for a while so wont be able to offer any more feedback. -- Ian Malcolm. London, ENGLAND. (NEWSGROUP REPLY PREFERRED) ianm[at]the[dash]malcolms[dot]freeserve[dot]co[dot]uk [at]=@, [dash]=- & [dot]=. *Warning* HTML & 32K emails -- NUL: 'Stingo' Albacore #1554 - 15' Early 60's, Uffa Fox designed, All varnished hot moulded wooden racing dinghy. |
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