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#11
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Bob Markus wrote:
I agree, does not seem likely. I'm a ham and lots of experience with VHF. Cannot explain it and I do not know why. But we could not receive with the Nav. lights on. LED lights are generally pulsed to save power. Crude electronics plus a long wire antenna up the mast radiating like crazy all the way fronm DC to almost light. A few turns through a ferrite ring at each end of the cable would probably help but there is no substitute for proper EMC filtering. YMMV. |
#12
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![]() "Chris Newport" wrote in message ... Bob Markus wrote: I agree, does not seem likely. I'm a ham and lots of experience with VHF. Cannot explain it and I do not know why. But we could not receive with the Nav. lights on. LED lights are generally pulsed to save power. Crude electronics plus a long wire antenna up the mast radiating like crazy all the way fronm DC to almost light. A few turns through a ferrite ring at each end of the cable would probably help but there is no substitute for proper EMC filtering. YMMV. Meindert, Terry, Chris Thanks for the info. Didn't know they would take something simple and complicate it. Switched to save power? How much power are we trying to save anyway? Maybe go back to oil lamps? And then we find out there's interference with the VHF. Sheesh...........what progress. |
#13
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"Gordon Wedman" wrote in message
news:Naa5f.17849$y_1.2003@edtnps89... Meindert, Terry, Chris Thanks for the info. Didn't know they would take something simple and complicate it. Switched to save power? How much power are we trying to save anyway? Ok, I'll do some math: A typical high-power LED draws 500 mA at 3V. If I use a ballast resistor to connect this LED to a battery at 12V, 9V will drop across the resistor at 500mA, which produces 4.5Watts of heat, which is quite substantial. The total power drawn from the battery is 6 Watt. With a switched regulator, there is (hardly) no voltage drop, so the power the LED uses (3V * 500mA = 1.5Watt) is the same as the power drawn from the battery. So more efficiency and the regulator also compensates for varying battery voltage which results in longer LED life. LEDs are quite picky on the proper voltage. 1/10th of a volt more than specified can shorten their lifespan from 50,000 hours to a few 100. This regulator prevents this. Meindert |
#14
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On 2005-10-19 07:13:06 +1000, "Meindert Sprang"
said: "Gordon Wedman" wrote in message news:Naa5f.17849$y_1.2003@edtnps89... Meindert, Terry, Chris Thanks for the info. Didn't know they would take something simple and complicate it. Switched to save power? How much power are we trying to save anyway? Ok, I'll do some math: A typical high-power LED draws 500 mA at 3V. If I use a ballast resistor to connect this LED to a battery at 12V, 9V will drop across the resistor at 500mA, which produces 4.5Watts of heat, which is quite substantial. The total power drawn from the battery is 6 Watt. With a switched regulator, there is (hardly) no voltage drop, so the power the LED uses (3V * 500mA = 1.5Watt) is the same as the power drawn from the battery. So more efficiency and the regulator also compensates for varying battery voltage which results in longer LED life. LEDs are quite picky on the proper voltage. 1/10th of a volt more than specified can shorten their lifespan from 50,000 hours to a few 100. This regulator prevents this. Meindert Don't forget that the LED is a current device. By that I mean light output is a function of forward current. Hence to get even illumination from multiple LEDs it is imperative that each LED be driven via a current regulated source. It is not sufficient to parallel them up in series with a dropping resistor. Sometimes simple things are complex. -- Regards, John Proctor VK3JP, VKV6789 S/V Chagall |
#15
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"John Proctor" wrote in message
news:2005101923295216807%lost@nowhereorg... Don't forget that the LED is a current device. By that I mean light output is a function of forward current. Hence to get even illumination from multiple LEDs it is imperative that each LED be driven via a current regulated source. It is not sufficient to parallel them up in series with a dropping resistor. Indeed. It's better to connect them in series (3 x 3V) and regulate the current though that. Needs only one regulator. Meindert |
#16
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"Meindert Sprang" wrote in message
... "Gordon Wedman" wrote in message news:Naa5f.17849$y_1.2003@edtnps89... Meindert, Terry, Chris Thanks for the info. Didn't know they would take something simple and complicate it. Switched to save power? How much power are we trying to save anyway? Ok, I'll do some math: A typical high-power LED draws 500 mA at 3V. If I use a ballast resistor to connect this LED to a battery at 12V, 9V will drop across the resistor at 500mA, which produces 4.5Watts of heat, which is quite substantial. The total power drawn from the battery is 6 Watt. With a switched regulator, there is (hardly) no voltage drop, so the power the LED uses (3V * 500mA = 1.5Watt) is the same as the power drawn from the battery. So more efficiency and the regulator also compensates for varying battery voltage which results in longer LED life. LEDs are quite picky on the proper voltage. 1/10th of a volt more than specified can shorten their lifespan from 50,000 hours to a few 100. This regulator prevents this. Meindert Not to be argumentative but......... It seems to me that a typical masthead lamp uses about 20 watts. So with the simple LED setup we are going from 20 watts to 6 watts. Not good enough though. We have to add some electronics to get it down to 1.5 watts (and add $$$ to the cost). Oh by the way, you can't transmit on your VHF now. It just seems that some companies are gold plating the faucets and then not doing a proper job of it too boot. Lastly, how big is a 5 watt resistor? I don't think this is all that much heat. What about the heat from the 12 and 20 watt cabin lamps? |
#17
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"Gordon Wedman" wrote in message
news:Nbv5f.26865$yS6.2060@clgrps12... Not to be argumentative but......... It seems to me that a typical masthead lamp uses about 20 watts. So with the simple LED setup we are going from 20 watts to 6 watts. Not good enough though. We have to add some electronics to get it down to 1.5 watts (and add $$$ to the cost). Oh by the way, you can't transmit on your VHF now. If done properly, it shouldn't be a problem. Lastly, how big is a 5 watt resistor? I don't think this is all that much heat. What about the heat from the 12 and 20 watt cabin lamps? Have you ever touched a 12 watt bulb when lit? To give you an indication, I have some electronics here with a voltage regulator. this regulator is one of those components of 1/2" in width and 3/4" in length, with a metal tab that can be screwed to a heatsink. In this design, the regulator burns 1.2 Watt. Without heatsink, it hurts when you touch it. 5 Watts is enough to solder. Meindert |
#18
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On 2005-10-20 01:56:05 +1000, "Meindert Sprang"
said: "John Proctor" wrote in message news:2005101923295216807%lost@nowhereorg... Don't forget that the LED is a current device. By that I mean light output is a function of forward current. Hence to get even illumination from multiple LEDs it is imperative that each LED be driven via a current regulated source. It is not sufficient to parallel them up in series with a dropping resistor. Indeed. It's better to connect them in series (3 x 3V) and regulate the current though that. Needs only one regulator. Meindert Unfortunately that approach does not allow for component spread. Statistically a batch of random LEDs will exhibit a reasonable spread in current to deliver equivalent luminosity. This is where the problem lies with using LEDs for backlight on displays etc. Where the illumination level must be even individual regulators are a must. In the case of marine lighting where you are mearly interested in the agregate light output a series connected string and regulator will suffice. -- Regards, John Proctor VK3JP, VKV6789 S/V Chagall |
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