Home |
Search |
Today's Posts |
#1
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
there is a simple way to stop the alternator delivering current when
the regulator has a failure ? Just not to overcharge the batteries. According to what I know the B+ cannot be open (diode break), so as the belt cannot be pulled away due to the water pump. Thanks for any idea. Manlio |
#2
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
Just disconnect the field wire from the alternator.
I wouldn't say that it couldn't happen but what sort of regulator failure do you envision that would result in overcharging the batteries? "Manlio" wrote in message news ![]() there is a simple way to stop the alternator delivering current when the regulator has a failure ? Just not to overcharge the batteries. According to what I know the B+ cannot be open (diode break), so as the belt cannot be pulled away due to the water pump. Thanks for any idea. Manlio |
#3
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
Followup to msg on Tue, 29 Apr 2008 01:18:41 +1000, "Faire dinkum"
: (Original msg on bottom) The output voltage is no more regulated and current flows continuously in order to start warming up the batteries, i.e. the regulator doesnt switch off the charge. I suppose it has been due to temperature failure as the solid state regulator may have similar problem. The alternator is a Valeo type with only the B+ Negative and D+ wires on output. I thought the D+ was the lamp line. I suppose you mean that D+ is the excitation line. ( I had the idea it was internally connected, then not reachable). Pls be so kind to confirm. Thanks for the fast answer. Manlio Just disconnect the field wire from the alternator. I wouldn't say that it couldn't happen but what sort of regulator failure do you envision that would result in overcharging the batteries? "Manlio" wrote in message news ![]() there is a simple way to stop the alternator delivering current when the regulator has a failure ? Just not to overcharge the batteries. According to what I know the B+ cannot be open (diode break), so as the belt cannot be pulled away due to the water pump. Thanks for any idea. Manlio |
#4
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
Manilo,
Valeo makes lots of different alternators. If the regulator is already shot, take all the wires off the alternator - you have little to loose. If you know how to and can take out the brush rack, that would be a good idea, too. The D+ lead is usually the lamp AND the start up excitation, but any unit run recently usually has enough residual field magnetism to self start anyway. Good Luck Guy Matt Colie Manlio wrote: Followup to msg on Tue, 29 Apr 2008 01:18:41 +1000, "Faire dinkum" : (Original msg on bottom) The output voltage is no more regulated and current flows continuously in order to start warming up the batteries, i.e. the regulator doesnt switch off the charge. I suppose it has been due to temperature failure as the solid state regulator may have similar problem. The alternator is a Valeo type with only the B+ Negative and D+ wires on output. I thought the D+ was the lamp line. I suppose you mean that D+ is the excitation line. ( I had the idea it was internally connected, then not reachable). Pls be so kind to confirm. Thanks for the fast answer. Manlio Just disconnect the field wire from the alternator. I wouldn't say that it couldn't happen but what sort of regulator failure do you envision that would result in overcharging the batteries? "Manlio" wrote in message news ![]() there is a simple way to stop the alternator delivering current when the regulator has a failure ? Just not to overcharge the batteries. According to what I know the B+ cannot be open (diode break), so as the belt cannot be pulled away due to the water pump. Thanks for any idea. Manlio |
#5
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
Followup to msg on Mon, 28 Apr 2008 12:35:00 -0400, Matt Colie
: (Original msg on bottom) unit run recently usually has enough residual field magnetism to self start anyway. that's exactly what I was thinking about !! :-(( Anyhow , now I am over the problem ... as at port .. then I am going to replace the regulator. But Could be interesting to find a solution when on sea, and without apparently any solution .. without additional problems :-)) Thanks Manlio |
#6
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
Manlio,
If you are at sea and your voltage regulator dies and full current is being sent to the field wire on the alternator you can make your own voltage regulator by wiring a light socket into the field wire. The resistance of a light bulb will reduce the current to the field and reduce the output of the alternator. You can change the available current by putting different wattage bulbs in the outlet and turn off the alternator by removing the bulb. Cheers Ansley Sawyer SV Pacem |
#7
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
The simple solution is to shut the engine down for a minute while you
disconnect B+. The problem with breaking the output and frying the diodes only happens when the alternator is putting out power. -- Glenn Ashmore I'm building a 45' cutter in strip/composite. Watch my progress (or lack there of) at: http://www.rutuonline.com Shameless Commercial Division: http://www.spade-anchor-us.com "Manlio" wrote in message ... Followup to msg on Tue, 29 Apr 2008 01:18:41 +1000, "Faire dinkum" : (Original msg on bottom) The output voltage is no more regulated and current flows continuously in order to start warming up the batteries, i.e. the regulator doesnt switch off the charge. I suppose it has been due to temperature failure as the solid state regulator may have similar problem. The alternator is a Valeo type with only the B+ Negative and D+ wires on output. I thought the D+ was the lamp line. I suppose you mean that D+ is the excitation line. ( I had the idea it was internally connected, then not reachable). Pls be so kind to confirm. Thanks for the fast answer. Manlio Just disconnect the field wire from the alternator. I wouldn't say that it couldn't happen but what sort of regulator failure do you envision that would result in overcharging the batteries? "Manlio" wrote in message news ![]() there is a simple way to stop the alternator delivering current when the regulator has a failure ? Just not to overcharge the batteries. According to what I know the B+ cannot be open (diode break), so as the belt cannot be pulled away due to the water pump. Thanks for any idea. Manlio |
#8
![]()
posted to rec.boats.electronics
|
|||
|
|||
![]()
Followup to msg on Mon, 28 Apr 2008 19:20:01 -0400, "Glenn Ashmore"
: (Original msg on bottom) Hi Glenn, your suggestion is simple and efficient. BTW I am hardly complaining myself as I could think it by myself .... I realize I am loosing scores ... :-)))) .... years are passing ... Thanks to all for ideas ! Manlio The simple solution is to shut the engine down for a minute while you disconnect B+. The problem with breaking the output and frying the diodes only happens when the alternator is putting out power. |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Cummins alternator question | General | |||
Cummins alternator question | Cruising | |||
alternator, voltage regulator question | Cruising | |||
Alternator question. | General |